Class 11 Mathematics · Chapter 6 · Test 9
Sequences in Real Life
38 MCQs Covers Exercise 6.11 applications of A.P. and G.P.: instalments, compound interest, population, tank, production, traffic, depreciation, motion and radioactivity.
38 questions · 35 min · 38 marks
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Sample questions
The first 5 of 38. Try each one, then tap to see the answer.
Question 1
A sum of Rs. 10400 is paid off in 40 instalments and each instalment is Rs. 10 more than the preceding one. The first instalment is:
- ARs. 55
- BRs. 60
- CRs. 65
- DRs. 70
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Answer: C
10400 = 20(2a + 390) gives 2a = 130 so a = 65.
Question 2
In the instalment problem (40 instalments, d = 10, first instalment Rs. 65) the last instalment is:
- ARs. 455
- BRs. 445
- CRs. 465
- DRs. 400
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Answer: A
a_40 = 65 + 39(10) = 455. Check: 40/2 (65+455) = 10400.
Question 3
Which formula is used to find the total paid in the instalments problem?
- AS_n = a1(1 - r^n)/(1 - r)
- Ba_n = a1 r^(n-1)
- CS_inf = a1/(1 - r)
- DS_n = n/2 [2a1 + (n-1)d]
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Answer: D
Equal increases of Rs. 10 each time form an A.P. so the total is S_n = n/2 [2a1 + (n-1)d].
Question 4
An investor invests Rs. 15000 at 6% annual compound interest for 8 years. The total amount is approximately:
- ARs. 22,200.00
- BRs. 23,907.72
- CRs. 25,342.19
- DRs. 22,554.45
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Answer: B
Amount = 15000(1.06)^8 = 23907.72. Rs. 22200 is the simple-interest value.
Question 5
In the compound interest problem the amount after 8 years is which term of the G.P. whose first term is the initial principal?
- A8th term
- B7th term
- C9th term
- D10th term
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Answer: C
The principal is a1 so the amount after 8 years is a9 = a1 r^8.
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