Class 12 Biology · Chapter 6 · Test 1
Mendel's Laws
45 MCQs
45 questions · 35 min · 45 marks
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Sample questions
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Question 1
In the monohybrid cross of Mendel, when a pure round-seeded plant was crossed with a wrinkled-seeded plant, all the F1 progeny were round-seeded, because of:
- ACo-dominance
- BIncomplete dominance
- CComplete dominance
- DEpistasis
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Answer: C
The round allele is completely dominant over the wrinkled allele so all F1 plants show the round trait.
Question 2
In a cross of AaBb x AaBb, what fraction of the offspring can be expected to express one of the two dominant alleles, but not both?
- A1/16
- B6/16
- C9/16
- D16/16
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Answer: B
A_bb gives 3/16 and aaB_ gives 3/16, so the total is 6/16.
Question 3
In which of these cases can two genes experience independent assortment?
- AThey are located in close proximity on the same chromosome.
- BCrossing over between the genes does not occur.
- CThey are located on different chromosomes or are far apart on the same chromosome.
- DThe expression of one gene does not affect the expression of the other.
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Answer: C
Genes on different chromosomes or far apart on the same chromosome assort independently.
Question 4
In pea plants, the allele for tall stalks (T) is dominant over short stalks (t). A cross between a tall plant and a short plant produces 43 tall and 47 short offspring. If one tall offspring is crossed with one short offspring, what genotype ratio is most likely?
- A1 TT : 2 Tt : 1 tt
- B3 Tt : 1 tt
- CAll Tt
- D1 Tt : 1 tt
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Answer: D
The 1:1 result shows the tall parent was Tt, so the tall offspring is Tt and crossing it with tt gives 1 Tt : 1 tt.
Question 5
Allele B produces black coat colour while b produces white. Allele C produces curly fur while c produces straight fur. In a cross between two BbCc parents, what fraction of offspring have black coat and straight fur?
- A3/16
- B9/16
- C3/4
- D16/16
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Answer: A
Black is 3/4 and straight fur is 1/4, so by the product rule the answer is 3/16.
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