Stability Constants and Stereoisomerism

36 MCQs

MCQs

36 questions · 30 min · 36 marks

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Sample questions

The first 5 of 36. Try each one, then tap to see the answer.

  1. Question 1

    The stability constant Kstab is:

    • AThe equilibrium constant for the formation of a complex ion
    • BThe rate constant for the decomposition of a complex
    • CThe solubility product
    • DThe acid dissociation constant
    Show answer

    Answer: A

    Kstab is the equilibrium constant for complex formation.

  2. Question 2

    Why is [H2O] omitted from the Kstab expression?

    • AWater is a gas
    • BWater is the solvent and its concentration is effectively constant
    • CWater does not take part in the reaction
    • DWater is a product
    Show answer

    Answer: B

    Since the solvent concentration stays constant it is left out.

  3. Question 3

    Which is the Kstab expression for [Cu(H2O)6]2+ + 4NH3 ⇌ [Cu(NH3)4(H2O)2]2+ + 4H2O?

    • A[Cu(NH3)4(H2O)2]2+ / [NH3]^4
    • B[Cu(H2O)6]2+[NH3]^4 / [Cu(NH3)4(H2O)2]2+
    • C[Cu(NH3)4(H2O)2]2+ / ([Cu(H2O)6]2+[NH3]^4)
    • D[Cu(NH3)4(H2O)2]2+[H2O]^4 / ([Cu(H2O)6]2+[NH3]^4)
    Show answer

    Answer: C

    Kstab = [complex] / ([aqua complex][ligand]^4) with water omitted.

  4. Question 4

    A higher log10 Kstab means the complex is:

    • ALess stable and easily decomposed
    • BInsoluble
    • CColourless
    • DMore stable with the equilibrium lying far to the right
    Show answer

    Answer: D

    A large Kstab means the complex is strongly favoured.

  5. Question 5

    A low log10 Kstab shows that:

    • AThe complex is less stable and its ligands are easily displaced
    • BThe complex is extremely stable
    • CThe complex is neutral
    • DThe metal is a non-metal
    Show answer

    Answer: A

    Low stability lets other ligands displace those present.

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