Class 9 Physics · Chapter 5 · Test 5
Work and Energy Calculations
35 MCQs
35 questions · 30 min · 35 marks
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Sample questions
The first 5 of 35. Try each one, then tap to see the answer.
Question 1
A force of 25 N acts on an object moving 4 m. If the force makes an angle of 60° with displacement, how much work is done?
- A25 J
- B50 J
- C75 J
- D100 J
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Answer: B
W = Fs cos θ = 25 × 4 × cos 60° = 50 J.
Question 2
A force acts perpendicular to the displacement of an object. The work done by this force is:
- AMaximum
- BNegative
- CZero
- DEqual to the object's kinetic energy
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Answer: C
W = Fs cos 90° = 0.
Question 3
A 12 N force acts opposite to the direction of displacement through 5 m. What is the work done by the force?
- A60 J
- B−60 J
- C17 J
- D−17 J
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Answer: B
W = Fs cos 180° = 12 × 5 × (−1) = −60 J.
Question 4
A force–displacement graph is a horizontal line at 8 N from 0 m to 6 m. What is the work done?
- A14 J
- B24 J
- C48 J
- D64 J
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Answer: C
Work equals the area under the force–displacement graph: W = 8 × 6 = 48 J.
Question 5
A constant force increases uniformly from 0 N to 20 N over a displacement of 5 m. What is the work done?
- A25 J
- B50 J
- C75 J
- D100 J
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Answer: B
The graph is a triangle, so W = ½ × 5 × 20 = 50 J.
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