Hydrocarbons Chapter 11

54 MCQ test checks your understanding of aliphatic and aromatic hydrocarbons and the naming and shapes of alkanes and cycloalkanes. It also covers free radical substitution, the preparation, structure and reactions of alkenes, carbocation stability and Markovnikov’s rule, conjugated dienes, isomerism and organic redox reactions. Each question is worth 1 mark, for a total of 56 marks. All questions are based only on the text you provided.

MCQs

54 questions · 40 min · 54 marks

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Sample questions

The first 5 of 54. Try each one, then tap to see the answer.

  1. Question 1

    An alkene undergoes ozonolysis followed by reduction with zinc dust and water to yield propanone and methanal. The alkene is:

    • A1-Butene
    • B2-Butene
    • C2-Methylpropene
    • D2-Methyl-2-butene
    Show answer

    Answer: C

    Propanone (3 carbons) and methanal (1 carbon) together have 4 carbons. Splitting (CH3)2C=CH2 at the double bond gives propanone and methanal.

  2. Question 2

    Which of the following reagents is typically used for the acid-catalyzed hydration of alkenes to form alcohols?

    • AH2/Ni
    • BO3 followed by Zn/H2O
    • CDilute H2SO4
    • DBr2 in CCl4
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    Answer: C

    Alkenes react with steam in the presence of H2SO4 as a catalyst to give alcohols.

  3. Question 3

    Halogenation of alkanes is an example of:

    • AElectrophilic substitution
    • BNucleophilic substitution
    • CFree-radical substitution
    • DOxidation
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    Answer: C

    Alkanes react with halogens in UV light through a free radical mechanism.

  4. Question 4

    Which of the following reactions can an alkane undergo?

    • AAddition
    • BSubstitution
    • CPolymerization
    • DElectrophilic addition
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    Answer: B

    Alkanes undergo free radical substitution and thermal and catalytic reactions. They do not undergo addition.

  5. Question 5

    What is the first step in the electrophilic addition reaction of alkenes?

    • AFormation of a carbanion
    • BAttack by a nucleophile
    • CAttack by an electrophile on the double bond
    • DFormation of a free radical
    Show answer

    Answer: C

    The electron-rich C=C is attacked by the electrophile and this gives a carbocation intermediate which then reacts with the nucleophile.

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